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(5x/6x-18)=(1/x-3)
We move all terms to the left:
(5x/6x-18)-((1/x-3))=0
Domain of the equation: 6x-18)!=0
x∈R
Domain of the equation: x-3))!=0We get rid of parentheses
x∈R
5x/6x-((1/x-3))-18=0
We calculate fractions
5x^2/6x^2+(-((1*6x)/6x^2-18=0
We add all the numbers together, and all the variables
5x^2/6x^2+(-((+1*6x)/6x^2-18=0
We calculate fractions
We do not support expression: x^4
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