(5x/7)+(1/14)=(7/28)

Solution for (5x/7)+(1/14)=(7/28) equation:

(5x/7)+(1/14)=(7/28)

We move all terms to the left:

(5x/7)+(1/14)-((7/28))=0

We add all the numbers together, and all the variables

(+5x/7)+(+1/14)-((+7/28))=0

We get rid of parentheses

5x/7+1/14-((+7/28))=0

We calculate fractions


3920x^2/()+()/()+()/()=0

We add all the numbers together, and all the variables

3920x^2/()+2=0

We multiply all the terms by the denominator


3920x^2+2*()=0

We add all the numbers together, and all the variables

3920x^2=0

a = 3920; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·3920·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{7840}=0$