(5x/7)=35

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Solution for (5x/7)=35 equation: 



(5x/7)=35

We move all terms to the left:

(5x/7)-(35)=0

We add all the numbers together, and all the variables

(+5x/7)-35=0

We get rid of parentheses

5x/7-35=0

We multiply all the terms by the denominator


5x-35*7=0

We add all the numbers together, and all the variables

5x-245=0

We move all terms containing x to the left, all other terms to the right

5x=245

x=245/5

x=49

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