(5x/8)+(x/2)=(17/8)-x

Solution for (5x/8)+(x/2)=(17/8)-x equation:

(5x/8)+(x/2)=(17/8)-x

We move all terms to the left:

(5x/8)+(x/2)-((17/8)-x)=0


Domain of the equation: 8)-x)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

(+5x/8)+(+x/2)-((+17/8)-x)=0

We get rid of parentheses

5x/8+x/2-((+17/8)-x)=0

We calculate fractions


512x^2/1024x+10x/1024x+()/1024x=0

We multiply all the terms by the denominator


512x^2+10x+()=0

We add all the numbers together, and all the variables

512x^2+10x=0

a = 512; b = 10; c = 0;
Δ = b2-4ac
Δ = 102-4·512·0
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{100}=10$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-10}{2*512}=\frac{-20}{1024}
=-5/256
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+10}{2*512}=\frac{0}{1024}
=0
$