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(5x/x-3)+9=2
We move all terms to the left:
(5x/x-3)+9-(2)=0
Domain of the equation: x-3)!=0We add all the numbers together, and all the variables
x∈R
(5x/x-3)+7=0
We get rid of parentheses
5x/x-3+7=0
We multiply all the terms by the denominator
5x-3*x+7*x=0
We add all the numbers together, and all the variables
9x=0
x=0/9
x=0
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