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(5x^2)=(2x-3)
We move all terms to the left:
(5x^2)-((2x-3))=0
We calculate terms in parentheses: -((2x-3)), so:We get rid of parentheses
(2x-3)
We get rid of parentheses
2x-3
Back to the equation:
-(2x-3)
5x^2-2x+3=0
a = 5; b = -2; c = +3;
Δ = b2-4ac
Δ = -22-4·5·3
Δ = -56
Delta is less than zero, so there is no solution for the equation
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