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(5x^2+2x-7)=(-3x^2+6x-9)
We move all terms to the left:
(5x^2+2x-7)-((-3x^2+6x-9))=0
We get rid of parentheses
-((-3x^2+6x-9))+5x^2+2x-7=0
We calculate terms in parentheses: -((-3x^2+6x-9)), so:We add all the numbers together, and all the variables
(-3x^2+6x-9)
We get rid of parentheses
-3x^2+6x-9
Back to the equation:
-(-3x^2+6x-9)
5x^2-(-3x^2+6x-9)+2x-7=0
We get rid of parentheses
5x^2+3x^2-6x+2x+9-7=0
We add all the numbers together, and all the variables
8x^2-4x+2=0
a = 8; b = -4; c = +2;
Δ = b2-4ac
Δ = -42-4·8·2
Δ = -48
Delta is less than zero, so there is no solution for the equation
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