(5x2-2x+3)=(x2-2x-3)

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Solution for (5x2-2x+3)=(x2-2x-3) equation: 



(5x^2-2x+3)=(x2-2x-3)

We move all terms to the left:

(5x^2-2x+3)-((x2-2x-3))=0

We add all the numbers together, and all the variables

-((+x^2-2x-3))+(5x^2-2x+3)=0

We get rid of parentheses

-((+x^2-2x-3))+5x^2-2x+3=0



We calculate terms in parentheses: -((+x^2-2x-3)), so:

(+x^2-2x-3)

We get rid of parentheses

x^2-2x-3

Back to the equation:

-(x^2-2x-3)



We add all the numbers together, and all the variables

5x^2-2x-(x^2-2x-3)+3=0

We get rid of parentheses

5x^2-x^2-2x+2x+3+3=0

We add all the numbers together, and all the variables

4x^2+6=0

a = 4; b = 0; c = +6;
Δ = b2-4ac
Δ = 02-4·4·6
Δ = -96
Delta is less than zero, so there is no solution for the equation

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