(5y+1)(4-y)=0

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Solution for (5y+1)(4-y)=0 equation:


Simplifying
(5y + 1)(4 + -1y) = 0

Reorder the terms:
(1 + 5y)(4 + -1y) = 0

Multiply (1 + 5y) * (4 + -1y)
(1(4 + -1y) + 5y * (4 + -1y)) = 0
((4 * 1 + -1y * 1) + 5y * (4 + -1y)) = 0
((4 + -1y) + 5y * (4 + -1y)) = 0
(4 + -1y + (4 * 5y + -1y * 5y)) = 0
(4 + -1y + (20y + -5y2)) = 0

Combine like terms: -1y + 20y = 19y
(4 + 19y + -5y2) = 0

Solving
4 + 19y + -5y2 = 0

Solving for variable 'y'.

Factor a trinomial.
(4 + -1y)(1 + 5y) = 0

Subproblem 1

Set the factor '(4 + -1y)' equal to zero and attempt to solve: Simplifying 4 + -1y = 0 Solving 4 + -1y = 0 Move all terms containing y to the left, all other terms to the right. Add '-4' to each side of the equation. 4 + -4 + -1y = 0 + -4 Combine like terms: 4 + -4 = 0 0 + -1y = 0 + -4 -1y = 0 + -4 Combine like terms: 0 + -4 = -4 -1y = -4 Divide each side by '-1'. y = 4 Simplifying y = 4

Subproblem 2

Set the factor '(1 + 5y)' equal to zero and attempt to solve: Simplifying 1 + 5y = 0 Solving 1 + 5y = 0 Move all terms containing y to the left, all other terms to the right. Add '-1' to each side of the equation. 1 + -1 + 5y = 0 + -1 Combine like terms: 1 + -1 = 0 0 + 5y = 0 + -1 5y = 0 + -1 Combine like terms: 0 + -1 = -1 5y = -1 Divide each side by '5'. y = -0.2 Simplifying y = -0.2

Solution

y = {4, -0.2}

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