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(5y+1)(5-y)=0
We add all the numbers together, and all the variables
(5y+1)(-1y+5)=0
We multiply parentheses ..
(-5y^2+25y-1y+5)=0
We get rid of parentheses
-5y^2+25y-1y+5=0
We add all the numbers together, and all the variables
-5y^2+24y+5=0
a = -5; b = 24; c = +5;
Δ = b2-4ac
Δ = 242-4·(-5)·5
Δ = 676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{676}=26$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-26}{2*-5}=\frac{-50}{-10} =+5 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+26}{2*-5}=\frac{2}{-10} =-1/5 $
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