(5y+1)+(3y-2)=-17

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Solution for (5y+1)+(3y-2)=-17 equation:



(5y+1)+(3y-2)=-17
We move all terms to the left:
(5y+1)+(3y-2)-(-17)=0
We add all the numbers together, and all the variables
(5y+1)+(3y-2)+17=0
We get rid of parentheses
5y+3y+1-2+17=0
We add all the numbers together, and all the variables
8y+16=0
We move all terms containing y to the left, all other terms to the right
8y=-16
y=-16/8
y=-2

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