(5y+10)+(5y+10)+(5y+6)+(5y+6)=(194+2y)

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Solution for (5y+10)+(5y+10)+(5y+6)+(5y+6)=(194+2y) equation: 



(5y+10)+(5y+10)+(5y+6)+(5y+6)=(194+2y)

We move all terms to the left:

(5y+10)+(5y+10)+(5y+6)+(5y+6)-((194+2y))=0

We add all the numbers together, and all the variables

(5y+10)+(5y+10)+(5y+6)+(5y+6)-((2y+194))=0

We get rid of parentheses

5y+5y+5y+5y-((2y+194))+10+10+6+6=0



We calculate terms in parentheses: -((2y+194)), so:

(2y+194)

We get rid of parentheses

2y+194

Back to the equation:

-(2y+194)



We add all the numbers together, and all the variables

20y-(2y+194)+32=0

We get rid of parentheses

20y-2y-194+32=0

We add all the numbers together, and all the variables

18y-162=0

We move all terms containing y to the left, all other terms to the right

18y=162

y=162/18

y=9

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