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(5y+10)=(3y+50)
We move all terms to the left:
(5y+10)-((3y+50))=0
We get rid of parentheses
5y-((3y+50))+10=0
We calculate terms in parentheses: -((3y+50)), so:We get rid of parentheses
(3y+50)
We get rid of parentheses
3y+50
Back to the equation:
-(3y+50)
5y-3y-50+10=0
We add all the numbers together, and all the variables
2y-40=0
We move all terms containing y to the left, all other terms to the right
2y=40
y=40/2
y=20
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