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(5y+12)(9y+11)-(8y+13)(5y+12)=0
We multiply parentheses ..
(+45y^2+55y+108y+132)-(8y+13)(5y+12)=0
We get rid of parentheses
45y^2+55y+108y-(8y+13)(5y+12)+132=0
We multiply parentheses ..
45y^2-(+40y^2+96y+65y+156)+55y+108y+132=0
We add all the numbers together, and all the variables
45y^2-(+40y^2+96y+65y+156)+163y+132=0
We get rid of parentheses
45y^2-40y^2-96y-65y+163y-156+132=0
We add all the numbers together, and all the variables
5y^2+2y-24=0
a = 5; b = 2; c = -24;
Δ = b2-4ac
Δ = 22-4·5·(-24)
Δ = 484
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{484}=22$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-22}{2*5}=\frac{-24}{10} =-2+2/5 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+22}{2*5}=\frac{20}{10} =2 $
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