(5y+2)(6+y)=0

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Solution for (5y+2)(6+y)=0 equation:



(5y+2)(6+y)=0
We add all the numbers together, and all the variables
(5y+2)(y+6)=0
We multiply parentheses ..
(+5y^2+30y+2y+12)=0
We get rid of parentheses
5y^2+30y+2y+12=0
We add all the numbers together, and all the variables
5y^2+32y+12=0
a = 5; b = 32; c = +12;
Δ = b2-4ac
Δ = 322-4·5·12
Δ = 784
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{784}=28$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(32)-28}{2*5}=\frac{-60}{10} =-6 $
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(32)+28}{2*5}=\frac{-4}{10} =-2/5 $

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