(5y+2)(y+4)=-3(5y+2)

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Solution for (5y+2)(y+4)=-3(5y+2) equation:


Simplifying
(5y + 2)(y + 4) = -3(5y + 2)

Reorder the terms:
(2 + 5y)(y + 4) = -3(5y + 2)

Reorder the terms:
(2 + 5y)(4 + y) = -3(5y + 2)

Multiply (2 + 5y) * (4 + y)
(2(4 + y) + 5y * (4 + y)) = -3(5y + 2)
((4 * 2 + y * 2) + 5y * (4 + y)) = -3(5y + 2)
((8 + 2y) + 5y * (4 + y)) = -3(5y + 2)
(8 + 2y + (4 * 5y + y * 5y)) = -3(5y + 2)
(8 + 2y + (20y + 5y2)) = -3(5y + 2)

Combine like terms: 2y + 20y = 22y
(8 + 22y + 5y2) = -3(5y + 2)

Reorder the terms:
8 + 22y + 5y2 = -3(2 + 5y)
8 + 22y + 5y2 = (2 * -3 + 5y * -3)
8 + 22y + 5y2 = (-6 + -15y)

Solving
8 + 22y + 5y2 = -6 + -15y

Solving for variable 'y'.

Reorder the terms:
8 + 6 + 22y + 15y + 5y2 = -6 + -15y + 6 + 15y

Combine like terms: 8 + 6 = 14
14 + 22y + 15y + 5y2 = -6 + -15y + 6 + 15y

Combine like terms: 22y + 15y = 37y
14 + 37y + 5y2 = -6 + -15y + 6 + 15y

Reorder the terms:
14 + 37y + 5y2 = -6 + 6 + -15y + 15y

Combine like terms: -6 + 6 = 0
14 + 37y + 5y2 = 0 + -15y + 15y
14 + 37y + 5y2 = -15y + 15y

Combine like terms: -15y + 15y = 0
14 + 37y + 5y2 = 0

Factor a trinomial.
(7 + y)(2 + 5y) = 0

Subproblem 1

Set the factor '(7 + y)' equal to zero and attempt to solve: Simplifying 7 + y = 0 Solving 7 + y = 0 Move all terms containing y to the left, all other terms to the right. Add '-7' to each side of the equation. 7 + -7 + y = 0 + -7 Combine like terms: 7 + -7 = 0 0 + y = 0 + -7 y = 0 + -7 Combine like terms: 0 + -7 = -7 y = -7 Simplifying y = -7

Subproblem 2

Set the factor '(2 + 5y)' equal to zero and attempt to solve: Simplifying 2 + 5y = 0 Solving 2 + 5y = 0 Move all terms containing y to the left, all other terms to the right. Add '-2' to each side of the equation. 2 + -2 + 5y = 0 + -2 Combine like terms: 2 + -2 = 0 0 + 5y = 0 + -2 5y = 0 + -2 Combine like terms: 0 + -2 = -2 5y = -2 Divide each side by '5'. y = -0.4 Simplifying y = -0.4

Solution

y = {-7, -0.4}

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