(5y+2)+(3y+5)=(10y-1)

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Solution for (5y+2)+(3y+5)=(10y-1) equation:


Simplifying
(5y + 2) + (3y + 5) = (10y + -1)

Reorder the terms:
(2 + 5y) + (3y + 5) = (10y + -1)

Remove parenthesis around (2 + 5y)
2 + 5y + (3y + 5) = (10y + -1)

Reorder the terms:
2 + 5y + (5 + 3y) = (10y + -1)

Remove parenthesis around (5 + 3y)
2 + 5y + 5 + 3y = (10y + -1)

Reorder the terms:
2 + 5 + 5y + 3y = (10y + -1)

Combine like terms: 2 + 5 = 7
7 + 5y + 3y = (10y + -1)

Combine like terms: 5y + 3y = 8y
7 + 8y = (10y + -1)

Reorder the terms:
7 + 8y = (-1 + 10y)

Remove parenthesis around (-1 + 10y)
7 + 8y = -1 + 10y

Solving
7 + 8y = -1 + 10y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-10y' to each side of the equation.
7 + 8y + -10y = -1 + 10y + -10y

Combine like terms: 8y + -10y = -2y
7 + -2y = -1 + 10y + -10y

Combine like terms: 10y + -10y = 0
7 + -2y = -1 + 0
7 + -2y = -1

Add '-7' to each side of the equation.
7 + -7 + -2y = -1 + -7

Combine like terms: 7 + -7 = 0
0 + -2y = -1 + -7
-2y = -1 + -7

Combine like terms: -1 + -7 = -8
-2y = -8

Divide each side by '-2'.
y = 4

Simplifying
y = 4

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