(5y+2)+(3y+7)=(13y-21)

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Solution for (5y+2)+(3y+7)=(13y-21) equation: 



(5y+2)+(3y+7)=(13y-21)

We move all terms to the left:

(5y+2)+(3y+7)-((13y-21))=0

We get rid of parentheses

5y+3y-((13y-21))+2+7=0



We calculate terms in parentheses: -((13y-21)), so:

(13y-21)

We get rid of parentheses

13y-21

Back to the equation:

-(13y-21)



We add all the numbers together, and all the variables

8y-(13y-21)+9=0

We get rid of parentheses

8y-13y+21+9=0

We add all the numbers together, and all the variables

-5y+30=0

We move all terms containing y to the left, all other terms to the right

-5y=-30

y=-30/-5

y=+6

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