(5y+2)+(3y+7)=10y-1

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Solution for (5y+2)+(3y+7)=10y-1 equation:


Simplifying
(5y + 2) + (3y + 7) = 10y + -1

Reorder the terms:
(2 + 5y) + (3y + 7) = 10y + -1

Remove parenthesis around (2 + 5y)
2 + 5y + (3y + 7) = 10y + -1

Reorder the terms:
2 + 5y + (7 + 3y) = 10y + -1

Remove parenthesis around (7 + 3y)
2 + 5y + 7 + 3y = 10y + -1

Reorder the terms:
2 + 7 + 5y + 3y = 10y + -1

Combine like terms: 2 + 7 = 9
9 + 5y + 3y = 10y + -1

Combine like terms: 5y + 3y = 8y
9 + 8y = 10y + -1

Reorder the terms:
9 + 8y = -1 + 10y

Solving
9 + 8y = -1 + 10y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-10y' to each side of the equation.
9 + 8y + -10y = -1 + 10y + -10y

Combine like terms: 8y + -10y = -2y
9 + -2y = -1 + 10y + -10y

Combine like terms: 10y + -10y = 0
9 + -2y = -1 + 0
9 + -2y = -1

Add '-9' to each side of the equation.
9 + -9 + -2y = -1 + -9

Combine like terms: 9 + -9 = 0
0 + -2y = -1 + -9
-2y = -1 + -9

Combine like terms: -1 + -9 = -10
-2y = -10

Divide each side by '-2'.
y = 5

Simplifying
y = 5

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