(5y+2)-(4y-1)=

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Solution for (5y+2)-(4y-1)= equation:


Simplifying
(5y + 2) + -1(4y + -1) = 0

Reorder the terms:
(2 + 5y) + -1(4y + -1) = 0

Remove parenthesis around (2 + 5y)
2 + 5y + -1(4y + -1) = 0

Reorder the terms:
2 + 5y + -1(-1 + 4y) = 0
2 + 5y + (-1 * -1 + 4y * -1) = 0
2 + 5y + (1 + -4y) = 0

Reorder the terms:
2 + 1 + 5y + -4y = 0

Combine like terms: 2 + 1 = 3
3 + 5y + -4y = 0

Combine like terms: 5y + -4y = 1y
3 + 1y = 0

Solving
3 + 1y = 0

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-3' to each side of the equation.
3 + -3 + 1y = 0 + -3

Combine like terms: 3 + -3 = 0
0 + 1y = 0 + -3
1y = 0 + -3

Combine like terms: 0 + -3 = -3
1y = -3

Divide each side by '1'.
y = -3

Simplifying
y = -3

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