(5y+29)=(7y-11)

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Solution for (5y+29)=(7y-11) equation: 



(5y+29)=(7y-11)

We move all terms to the left:

(5y+29)-((7y-11))=0

We get rid of parentheses

5y-((7y-11))+29=0



We calculate terms in parentheses: -((7y-11)), so:

(7y-11)

We get rid of parentheses

7y-11

Back to the equation:

-(7y-11)



We get rid of parentheses

5y-7y+11+29=0

We add all the numbers together, and all the variables

-2y+40=0

We move all terms containing y to the left, all other terms to the right

-2y=-40

y=-40/-2

y=+20

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