(5y+29+3y=-20)

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Solution for (5y+29+3y=-20) equation: 



(5y+29+3y=-20)

We move all terms to the left:

(5y+29+3y-(-20))=0



We calculate terms in parentheses: +(5y+29+3y-(-20)), so:

5y+29+3y-(-20)

determiningTheFunctionDomain
5y+3y+29-(-20)

We add all the numbers together, and all the variables

8y+49

Back to the equation:

+(8y+49)



We get rid of parentheses

8y+49=0

We move all terms containing y to the left, all other terms to the right

8y=-49

y=-49/8

y=-6+1/8

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