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(5y+3)=(3y+5)
We move all terms to the left:
(5y+3)-((3y+5))=0
We get rid of parentheses
5y-((3y+5))+3=0
We calculate terms in parentheses: -((3y+5)), so:We get rid of parentheses
(3y+5)
We get rid of parentheses
3y+5
Back to the equation:
-(3y+5)
5y-3y-5+3=0
We add all the numbers together, and all the variables
2y-2=0
We move all terms containing y to the left, all other terms to the right
2y=2
y=2/2
y=1
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