(5y+4)(3+y)=0

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Solution for (5y+4)(3+y)=0 equation:


Simplifying
(5y + 4)(3 + y) = 0

Reorder the terms:
(4 + 5y)(3 + y) = 0

Multiply (4 + 5y) * (3 + y)
(4(3 + y) + 5y * (3 + y)) = 0
((3 * 4 + y * 4) + 5y * (3 + y)) = 0
((12 + 4y) + 5y * (3 + y)) = 0
(12 + 4y + (3 * 5y + y * 5y)) = 0
(12 + 4y + (15y + 5y2)) = 0

Combine like terms: 4y + 15y = 19y
(12 + 19y + 5y2) = 0

Solving
12 + 19y + 5y2 = 0

Solving for variable 'y'.

Factor a trinomial.
(3 + y)(4 + 5y) = 0

Subproblem 1

Set the factor '(3 + y)' equal to zero and attempt to solve: Simplifying 3 + y = 0 Solving 3 + y = 0 Move all terms containing y to the left, all other terms to the right. Add '-3' to each side of the equation. 3 + -3 + y = 0 + -3 Combine like terms: 3 + -3 = 0 0 + y = 0 + -3 y = 0 + -3 Combine like terms: 0 + -3 = -3 y = -3 Simplifying y = -3

Subproblem 2

Set the factor '(4 + 5y)' equal to zero and attempt to solve: Simplifying 4 + 5y = 0 Solving 4 + 5y = 0 Move all terms containing y to the left, all other terms to the right. Add '-4' to each side of the equation. 4 + -4 + 5y = 0 + -4 Combine like terms: 4 + -4 = 0 0 + 5y = 0 + -4 5y = 0 + -4 Combine like terms: 0 + -4 = -4 5y = -4 Divide each side by '5'. y = -0.8 Simplifying y = -0.8

Solution

y = {-3, -0.8}

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