(5y+6)(1-y)=0

Solution for (5y+6)(1-y)=0 equation:

(5y+6)(1-y)=0

We add all the numbers together, and all the variables

(5y+6)(-1y+1)=0

We multiply parentheses ..

(-5y^2+5y-6y+6)=0

We get rid of parentheses

-5y^2+5y-6y+6=0

We add all the numbers together, and all the variables

-5y^2-1y+6=0

a = -5; b = -1; c = +6;
Δ = b2-4ac
Δ = -12-4·(-5)·6
Δ = 121
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{121}=11$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-11}{2*-5}=\frac{-10}{-10}
=1
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+11}{2*-5}=\frac{12}{-10}
=-1+1/5
$