(5y+6)(4+y)=0

Solution for (5y+6)(4+y)=0 equation:

(5y+6)(4+y)=0

We add all the numbers together, and all the variables

(5y+6)(y+4)=0

We multiply parentheses ..

(+5y^2+20y+6y+24)=0

We get rid of parentheses

5y^2+20y+6y+24=0

We add all the numbers together, and all the variables

5y^2+26y+24=0

a = 5; b = 26; c = +24;
Δ = b2-4ac
Δ = 262-4·5·24
Δ = 196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{196}=14$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(26)-14}{2*5}=\frac{-40}{10}
=-4
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(26)+14}{2*5}=\frac{-12}{10}
=-1+1/5
$