(5y+8)-3(y-4)=-8y-4(9-y)+2y

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Solution for (5y+8)-3(y-4)=-8y-4(9-y)+2y equation:



(5y+8)-3(y-4)=-8y-4(9-y)+2y
We move all terms to the left:
(5y+8)-3(y-4)-(-8y-4(9-y)+2y)=0
We add all the numbers together, and all the variables
(5y+8)-3(y-4)-(-8y-4(-1y+9)+2y)=0
We multiply parentheses
(5y+8)-3y-(-8y-4(-1y+9)+2y)+12=0
We get rid of parentheses
5y-3y-(-8y-4(-1y+9)+2y)+8+12=0
We calculate terms in parentheses: -(-8y-4(-1y+9)+2y), so:
-8y-4(-1y+9)+2y
We add all the numbers together, and all the variables
-6y-4(-1y+9)
We multiply parentheses
-6y+4y-36
We add all the numbers together, and all the variables
-2y-36
Back to the equation:
-(-2y-36)
We add all the numbers together, and all the variables
2y-(-2y-36)+20=0
We get rid of parentheses
2y+2y+36+20=0
We add all the numbers together, and all the variables
4y+56=0
We move all terms containing y to the left, all other terms to the right
4y=-56
y=-56/4
y=-14

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