(5y-12)=(-5y-1)

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Solution for (5y-12)=(-5y-1) equation: 



(5y-12)=(-5y-1)

We move all terms to the left:

(5y-12)-((-5y-1))=0

We get rid of parentheses

5y-((-5y-1))-12=0



We calculate terms in parentheses: -((-5y-1)), so:

(-5y-1)

We get rid of parentheses

-5y-1

Back to the equation:

-(-5y-1)



We get rid of parentheses

5y+5y+1-12=0

We add all the numbers together, and all the variables

10y-11=0

We move all terms containing y to the left, all other terms to the right

10y=11

y=11/10

y=1+1/10

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