(5y-2)/3=(y+3)/4

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Solution for (5y-2)/3=(y+3)/4 equation:



(5y-2)/3=(y+3)/4
We move all terms to the left:
(5y-2)/3-((y+3)/4)=0
We calculate fractions
5y/()+(-((y+3)*3)/()=0
We calculate terms in parentheses: +(-((y+3)*3)/(), so:
-((y+3)*3)/(
We multiply all the terms by the denominator
-((y+3)*3)
We calculate terms in parentheses: -((y+3)*3), so:
(y+3)*3
We multiply parentheses
3y+9
Back to the equation:
-(3y+9)
We get rid of parentheses
-3y-9
Back to the equation:
+(-3y-9)
We get rid of parentheses
5y/()-3y-9=0
We multiply all the terms by the denominator
5y-3y*()-9*()=0
We add all the numbers together, and all the variables
5y-3y*()=0

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