(5y-3)(1-y)=0

Solution for (5y-3)(1-y)=0 equation:

(5y-3)(1-y)=0

We add all the numbers together, and all the variables

(5y-3)(-1y+1)=0

We multiply parentheses ..

(-5y^2+5y+3y-3)=0

We get rid of parentheses

-5y^2+5y+3y-3=0

We add all the numbers together, and all the variables

-5y^2+8y-3=0

a = -5; b = 8; c = -3;
Δ = b2-4ac
Δ = 82-4·(-5)·(-3)
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-2}{2*-5}=\frac{-10}{-10}
=1
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+2}{2*-5}=\frac{-6}{-10}
=3/5
$