(5y-3)(2-y)=0

Solution for (5y-3)(2-y)=0 equation:

(5y-3)(2-y)=0

We add all the numbers together, and all the variables

(5y-3)(-1y+2)=0

We multiply parentheses ..

(-5y^2+10y+3y-6)=0

We get rid of parentheses

-5y^2+10y+3y-6=0

We add all the numbers together, and all the variables

-5y^2+13y-6=0

a = -5; b = 13; c = -6;
Δ = b2-4ac
Δ = 132-4·(-5)·(-6)
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{49}=7$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(13)-7}{2*-5}=\frac{-20}{-10}
=+2
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(13)+7}{2*-5}=\frac{-6}{-10}
=3/5
$