(5y-3)*y=36

Solution for (5y-3)*y=36 equation:

(5y-3)*y=36

We move all terms to the left:

(5y-3)*y-(36)=0

We multiply parentheses

5y^2-3y-36=0

a = 5; b = -3; c = -36;
Δ = b2-4ac
Δ = -32-4·5·(-36)
Δ = 729
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{729}=27$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-27}{2*5}=\frac{-24}{10}
=-2+2/5
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+27}{2*5}=\frac{30}{10}
=3
$