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(5y-3/2y+1)=2/5
We move all terms to the left:
(5y-3/2y+1)-(2/5)=0
Domain of the equation: 2y+1)!=0We add all the numbers together, and all the variables
y∈R
(5y-3/2y+1)-(+2/5)=0
We get rid of parentheses
5y-3/2y+1-2/5=0
We calculate fractions
There is no solution for this equation
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