(5y-4)/6=(4y+1)-(3y+10)/2

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Solution for (5y-4)/6=(4y+1)-(3y+10)/2 equation: 



(5y-4)/6=(4y+1)-(3y+10)/2

We move all terms to the left:

(5y-4)/6-((4y+1)-(3y+10)/2)=0

We calculate fractions


5y/()+(-((4y+1)-(3y+10)*6)/()=0



We calculate terms in parentheses: +(-((4y+1)-(3y+10)*6)/(), so:

-((4y+1)-(3y+10)*6)/(

We multiply all the terms by the denominator


-((4y+1)-(3y+10)*6)



We calculate terms in parentheses: -((4y+1)-(3y+10)*6), so:

(4y+1)-(3y+10)*6

We multiply parentheses

(4y+1)-18y-60

We get rid of parentheses

4y-18y+1-60

We add all the numbers together, and all the variables

-14y-59

Back to the equation:

-(-14y-59)



We get rid of parentheses

14y+59

Back to the equation:

+(14y+59)



We get rid of parentheses

5y/()+14y+59=0

We multiply all the terms by the denominator


5y+14y*()+59*()=0

We add all the numbers together, and all the variables

5y+14y*()=0

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