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(5y-6)(4-y)=0
We add all the numbers together, and all the variables
(5y-6)(-1y+4)=0
We multiply parentheses ..
(-5y^2+20y+6y-24)=0
We get rid of parentheses
-5y^2+20y+6y-24=0
We add all the numbers together, and all the variables
-5y^2+26y-24=0
a = -5; b = 26; c = -24;
Δ = b2-4ac
Δ = 262-4·(-5)·(-24)
Δ = 196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{196}=14$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(26)-14}{2*-5}=\frac{-40}{-10} =+4 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(26)+14}{2*-5}=\frac{-12}{-10} =1+1/5 $
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