(5y-6)+(4y+3)=141

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Solution for (5y-6)+(4y+3)=141 equation: 



(5y-6)+(4y+3)=141

We move all terms to the left:

(5y-6)+(4y+3)-(141)=0

We get rid of parentheses

5y+4y-6+3-141=0

We add all the numbers together, and all the variables

9y-144=0

We move all terms containing y to the left, all other terms to the right

9y=144

y=144/9

y=16

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