(5y-8)(2+y)=0

Solution for (5y-8)(2+y)=0 equation:

(5y-8)(2+y)=0

We add all the numbers together, and all the variables

(5y-8)(y+2)=0

We multiply parentheses ..

(+5y^2+10y-8y-16)=0

We get rid of parentheses

5y^2+10y-8y-16=0

We add all the numbers together, and all the variables

5y^2+2y-16=0

a = 5; b = 2; c = -16;
Δ = b2-4ac
Δ = 22-4·5·(-16)
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{324}=18$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-18}{2*5}=\frac{-20}{10}
=-2
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+18}{2*5}=\frac{16}{10}
=1+3/5
$