(5z+1)/5=(2z-3)/2

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Solution for (5z+1)/5=(2z-3)/2 equation: 



(5z+1)/5=(2z-3)/2

We move all terms to the left:

(5z+1)/5-((2z-3)/2)=0

We calculate fractions


5z/()+(-((2z-3)*5)/()=0



We calculate terms in parentheses: +(-((2z-3)*5)/(), so:

-((2z-3)*5)/(

We multiply all the terms by the denominator


-((2z-3)*5)



We calculate terms in parentheses: -((2z-3)*5), so:

(2z-3)*5

We multiply parentheses

10z-15

Back to the equation:

-(10z-15)



We get rid of parentheses

-10z+15

Back to the equation:

+(-10z+15)



We get rid of parentheses

5z/()-10z+15=0

We multiply all the terms by the denominator


5z-10z*()+15*()=0

We add all the numbers together, and all the variables

5z-10z*()=0

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