(5z+3)(1+z)=0

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Solution for (5z+3)(1+z)=0 equation:



(5z+3)(1+z)=0
We add all the numbers together, and all the variables
(5z+3)(z+1)=0
We multiply parentheses ..
(+5z^2+5z+3z+3)=0
We get rid of parentheses
5z^2+5z+3z+3=0
We add all the numbers together, and all the variables
5z^2+8z+3=0
a = 5; b = 8; c = +3;
Δ = b2-4ac
Δ = 82-4·5·3
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-2}{2*5}=\frac{-10}{10} =-1 $
$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+2}{2*5}=\frac{-6}{10} =-3/5 $

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