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(5z+4)(6-z)=0
We add all the numbers together, and all the variables
(5z+4)(-1z+6)=0
We multiply parentheses ..
(-5z^2+30z-4z+24)=0
We get rid of parentheses
-5z^2+30z-4z+24=0
We add all the numbers together, and all the variables
-5z^2+26z+24=0
a = -5; b = 26; c = +24;
Δ = b2-4ac
Δ = 262-4·(-5)·24
Δ = 1156
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1156}=34$$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(26)-34}{2*-5}=\frac{-60}{-10} =+6 $$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(26)+34}{2*-5}=\frac{8}{-10} =-4/5 $
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