(5z-3)+(18z+3)=161

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Solution for (5z-3)+(18z+3)=161 equation: 



(5z-3)+(18z+3)=161

We move all terms to the left:

(5z-3)+(18z+3)-(161)=0

We get rid of parentheses

5z+18z-3+3-161=0

We add all the numbers together, and all the variables

23z-161=0

We move all terms containing z to the left, all other terms to the right

23z=161

z=161/23

z=7

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