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(5z-3)/2z=8/9
We move all terms to the left:
(5z-3)/2z-(8/9)=0
Domain of the equation: 2z!=0We add all the numbers together, and all the variables
z!=0/2
z!=0
z∈R
(5z-3)/2z-(+8/9)=0
We get rid of parentheses
(5z-3)/2z-8/9=0
We calculate fractions
(45z-27)/18z+(-16z)/18z=0
We multiply all the terms by the denominator
(45z-27)+(-16z)=0
We get rid of parentheses
45z-16z-27=0
We add all the numbers together, and all the variables
29z-27=0
We move all terms containing z to the left, all other terms to the right
29z=27
z=27/29
z=27/29
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