(5z-7)(4z+5)=(10z(2z-1))

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Solution for (5z-7)(4z+5)=(10z(2z-1)) equation: 



(5z-7)(4z+5)=(10z(2z-1))

We move all terms to the left:

(5z-7)(4z+5)-((10z(2z-1)))=0

We multiply parentheses ..

(+20z^2+25z-28z-35)-((10z(2z-1)))=0



We calculate terms in parentheses: -((10z(2z-1))), so:

(10z(2z-1))



We calculate terms in parentheses: +(10z(2z-1)), so:

10z(2z-1)

We multiply parentheses

20z^2-10z

Back to the equation:

+(20z^2-10z)



We get rid of parentheses

20z^2-10z

Back to the equation:

-(20z^2-10z)



We get rid of parentheses

20z^2-20z^2+25z-28z+10z-35=0

We add all the numbers together, and all the variables

7z-35=0

We move all terms containing z to the left, all other terms to the right

7z=35

z=35/7

z=5

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