(6(2x-1)-10)/(2x+1)=x

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Solution for (6(2x-1)-10)/(2x+1)=x equation: 



(6(2x-1)-10)/(2x+1)=x

We move all terms to the left:

(6(2x-1)-10)/(2x+1)-(x)=0



Domain of the equation: (2x+1)!=0

We move all terms containing x to the left, all other terms to the right

2x!=-1

x!=-1/2

x!=-1/2

x∈R



We add all the numbers together, and all the variables

-1x+(6(2x-1)-10)/(2x+1)=0

We multiply all the terms by the denominator


-1x*(2x+1)+(6(2x-1)-10)=0



We calculate terms in parentheses: +(6(2x-1)-10), so:

6(2x-1)-10

We multiply parentheses

12x-6-10

We add all the numbers together, and all the variables

12x-16

Back to the equation:

+(12x-16)



We multiply parentheses

-2x^2-x+(12x-16)=0

We get rid of parentheses

-2x^2-x+12x-16=0

We add all the numbers together, and all the variables

-2x^2+11x-16=0

a = -2; b = 11; c = -16;
Δ = b2-4ac
Δ = 112-4·(-2)·(-16)
Δ = -7
Delta is less than zero, so there is no solution for the equation

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