(6(4a/3-2)-3)+(2a+6)=(3a-10)+(5a+1)

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Solution for (6(4a/3-2)-3)+(2a+6)=(3a-10)+(5a+1) equation: 



(6(4a/3-2)-3)+(2a+6)=(3a-10)+(5a+1)

We move all terms to the left:

(6(4a/3-2)-3)+(2a+6)-((3a-10)+(5a+1))=0

We get rid of parentheses

(6(4a/3-2)-3)+2a-((3a-10)+(5a+1))+6=0

We multiply all the terms by the denominator


(6(4a+2a*3-2)-3)-(((3a-10)+(5a+1)))*3-2)-3)+6*3-2)-3)=0



We calculate terms in parentheses: +(6(4a+2a*3-2)-3), so:

6(4a+2a*3-2)-3

We multiply parentheses

24a+36a-12-3

We add all the numbers together, and all the variables

60a-15

Back to the equation:

+(60a-15)



We add all the numbers together, and all the variables

(60a-15)-(((3a-10)+(5a+1)))*3=0

We get rid of parentheses

60a-(((3a-10)+(5a+1)))*3-15=0

We move all terms containing a to the left, all other terms to the right

60a-(((3a-10)+(5a+1)))*3=15

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