(6)/(w+1)=()/((w-3)(w+))

Solution for (6)/(w+1)=()/((w-3)(w+)) equation:

(6)/(w+1)=()/((w-3)(w+))

We move all terms to the left:

(6)/(w+1)-(()/((w-3)(w+)))=0


Domain of the equation: (w+1)!=0

We move all terms containing w to the left, all other terms to the right

w!=-1

w∈R



Domain of the equation: ((w-3)(w+)))!=0

w∈R


We add all the numbers together, and all the variables

6/(w+1)-(()/((w-3)(+w)))=0

We multiply parentheses ..

-(()/((+w^2-3w)))+6/(w+1)=0

We calculate fractions


(-(()*(w+1))/(((+w^2-3w)))*w+(6*((+w^2-3w))))/(((+w^2-3w)))*w=0

We can not solve this equation