(6*1/3)*(4a+1)=(6+1/2)*a

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Solution for (6*1/3)*(4a+1)=(6+1/2)*a equation: 



(6*1/3)(4a+1)=(6+1/2)*a

We move all terms to the left:

(6*1/3)(4a+1)-((6+1/2)*a)=0



Domain of the equation: 3)(4a+1)!=0

a∈R





Domain of the equation: 2)*a)!=0

a!=0/1

a!=0

a∈R



We add all the numbers together, and all the variables

2(4a+1)-((1/2+6)*a)=0

We multiply parentheses

8a-((1/2+6)*a)+2=0

We multiply all the terms by the denominator


8a*2+6)*a)-((1+6)*a)+2*2=0

We add all the numbers together, and all the variables

8a*2+6)*a)-(7*a)+2*2=0

Wy multiply elements

16a+6)*a)-(7*a)+2*2=0

We add all the numbers together, and all the variables

16a+6)*a)-(+7a)+2*2=0

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