(6+(15/x))/(x+(5/2))

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Solution for (6+(15/x))/(x+(5/2)) equation: 


D( x )

x = 0

x+5/2 = 0

x = 0

x = 0

x+5/2 = 0

x+5/2 = 0

x+5/2 = 0 // - 5/2

x = -5/2

x in (-oo:-5/2) U (-5/2:0) U (0:+oo)

(15/x+6)/(x+5/2) = 0

(15*x^-1+6)/(x+5/2) = 0

15*x^-1 = -6 // : 15

x^-1 = -2/5

-1 < 0

1/(x^1) = -2/5 // * x^1

1 = -2/5*x^1 // : -2/5

-5/2 = x^1

x = -5/2

x in { -5/2} 

x belongs to the empty set

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