(6+2i)(6-2i)=0

Solution for (6+2i)(6-2i)=0 equation:

(6+2i)(6-2i)=0

We add all the numbers together, and all the variables

(2i+6)(-2i+6)=0

We multiply parentheses ..

(-4i^2+12i-12i+36)=0

We get rid of parentheses

-4i^2+12i-12i+36=0

We add all the numbers together, and all the variables

-4i^2+36=0

a = -4; b = 0; c = +36;
Δ = b2-4ac
Δ = 02-4·(-4)·36
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$i_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$i_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{576}=24$
$i_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-24}{2*-4}=\frac{-24}{-8}
=+3
$
$i_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+24}{2*-4}=\frac{24}{-8}
=-3
$