(6+2x)+2(4+4x)=62

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Solution for (6+2x)+2(4+4x)=62 equation: 



(6+2x)+2(4+4x)=62

We move all terms to the left:

(6+2x)+2(4+4x)-(62)=0

We add all the numbers together, and all the variables

(2x+6)+2(4x+4)-62=0

We multiply parentheses

(2x+6)+8x+8-62=0

We get rid of parentheses

2x+8x+6+8-62=0

We add all the numbers together, and all the variables

10x-48=0

We move all terms containing x to the left, all other terms to the right

10x=48

x=48/10

x=4+4/5

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